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SELECT $PARTITION.PFNExample1_Right(39) SELECT $PARTITION.PFNExample1_Right(40) SELECT $PARTITION.PFNExample1_Right(41)

To store the user s input, you can assign it to a variable, like this:

containing resistance and reactance Illustration for Problems 16-24 and 16-25

Next, you can ALTER the function to remove a boundary value, which effectively removes a partition by merging two neighboring partitions into one. The following code will remove boundary value 10 from our example function:

Even if you assign an empty string to the default answer parameter, the OK button (or its equivalent) is still available for the user to click without entering text in the text-entry field So if you need the user to enter text, you ll need to check that the field isn t blank We ll look at an example of how to do this in the next chapter

ALTER PARTITION FUNCTION PFNExample1_Right() MERGE RANGE (10);

across R and X Again, this differs from the applied voltage! The simple dc rule does not work here, for the same reason it didn t work in the scenario of Problem 16-21

Now we have the result of only three boundary values (20, 30, 40) because we removed 10 as a boundary value. Therefore, we re now back to only four partitions, but we ve moved the range forward a bit:

If the information the user is typing in the text-entry field needs to be protected from casual snooping, add the with hidden answer parameter to the display dialog statement This parameter makes Mac OS X display the user s input as bullet characters rather than actual characters for security

{NULL, MinInt ... 19}, {20 ... 29}, {30 ... 39}, {40 ... MaxInt}

Problem 16-24 Suppose a parallel RX circuit (shown by the generic block diagram of Fig 16-12) has R = 300 and X = 200 The ac supply voltage is 500 V rms What is the total current drawn from the ac supply First, find the square of the absolute-value impedance, remembering the formula for parallel circuits: Z 2 = R 2X 2/(R 2 + X 2) = 360,000/1300 = 277 The absolute-value impedance Z is the square root of 277, or 166 The total current is therefore I = E/Z = 50/166 = 301 A rms Problem 16-25 What are the rms currents through the resistance and the reactance, respectively, in the circuit described in Problem 16-24 The Ohm s Law formulas for dc will work here For the resistance, IR = E/R = 500/300 = 167 A rms For the reactance, IX = E/X = 500/( 200) = 25 A rms Note that these currents don t add up to 301 A, the total current The reason for this is the same as the reason ac voltages don t add arithmetically in ac circuits that contain reactance The constituent currents, IR and IX, differ in phase Vectorially, they add up to 301 A rms, but arithmetically, they don t

1 In AppleScript Editor, press z-N to create a new script 2 Create a display dialog statement that includes the default answer parameter with

It s important to realize the dynamic nature of the partition function, because it allows partitions to be added and removed from a partition function and also from any partitioned table that uses that function.

Using the SWITCH operation is conceptually much simpler than SPLIT and MERGE. All you do is ALTER the table and tell it what to swap. For example, in figure 2 we want to swap data into partitioned table P, partition 3, from staging table S. All that s required is this statement:

.

sample text as shown here:

ALTER TABLE dbo.P SWITCH PARTITION 3 TO dbo.S;

In this case, staging table S was preloaded with data and an empty partition 3 was created using the SPLIT option. Then the ALTER TABLE with SWITCH command swaps the two, and in a matter of milliseconds the data from table S is in partition 3. Conversely, figure 3 shows data being swapped out of the tail of a partitioned table. Partition 1 has data we want to put into the staging table S. This is the command:

display dialog "How old are you " default answer "25"